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  • Subtract: 3a (a + b + c ) – 2 b (a – b + c) from 4c ( – a + b + c )

Q : 5      (d)  Subtract:  \small 3a(a+b+c)-2b(a-b+c)  from  \small 4c(-a+b+c)

Answers (1)

best_answer

Solving brackets :

                         3a(a+b+c)-2b(a-b+c) = 3a^2+3ab+3ac - 2ab+2b^2-2bc

                                                                                       = 3a^2+ab+3ac+ 2b^2-2bc

and                 \small 4c(-a+b+c) = -4ac +4bc + 4c^2

Subtracting :                 \small -4ac +4bc + 4c^2 -(3a^2 + ab + 3ac+2b^2-2bc)

                                    \small = -4ac + 4bc+4c^2-3a^2-ab-3ac-2b^2+2bc

                                   \small =-3a^2 -2b^2+4c^2-ab+ 6bc-7ac

Posted by

Devendra Khairwa

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