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  • Suppose India had a target of producing by 2020 AD, 200,000 MW of electric power, ten percent of which was to be obtained from nuclear power plants

Q. 13.31 Suppose India had a target of producing by 2020 AD, 200,000 MW of electric power, ten percent of which was to be obtained from nuclear power plants. Suppose we are given that, on an average, the efficiency of utilization (i.e. conversion to electric energy) of thermal energy produced in a reactor was 25%. How much amount of fissionable uranium would our country need per year by 2020? Take the heat energy per fission of 235U to be about 200MeV.

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Let the amount of energy to be produced using nuclear power per year in 2020 is E

E=\frac{200000\times 10^{6}\times 0.1\times 365\times 24\times 3600}{0.25}\ J     (Only 10% of the required electrical energy is to be produced by Nuclear power and only 25% of                                                                                                         thermo-nuclear is successfully converted into electrical energy)

Amount of Uranium required to produce this much energy is M

=\frac{200000\times 10^{6}\times 0.1\times 365\times 24\times 3600\times 235}{0.25\times 200\times 10^{6}\times 1.6\times 10^{-19}\times 6.023\times 10^{23}\times 1000}    (NA=6.023\times1023, Atomic mass of Uranium is 235 g)

=3.076\times104 kg

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