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  • The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is (A) 14 (B) 28 (C) 8 (D) 6

The area of a triangle with vertices A (3, 0), B (7, 0) and C (8, 4) is

(A) 14

(B) 28

(C) 8

(D) 6

Answers (1)

The given vertices are A(3, 0), B(7, 0) and C(8, 4)

\\$ Area of $\Delta ABC = \frac{1}{2} [x\textsubscript{1}(y\textsubscript{2} - y\textsubscript{3}) + x\textsubscript{2}(y\textsubscript{3} - y\textsubscript{1}) + x\textsubscript{3}(y\textsubscript{1} - y\textsubscript{2})]\\ = \frac{1}{2} [3(0 - 4) + 7(4 - 0) + 8(0 - 0)]\\ = \frac{1}{2} [-12 + 28 + 0]\\ = \frac{1}{2} [16] = 8\\ $Area of $\Delta ABC = 8\\

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