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The atomic number of \text {Mn, Fe and Co} are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complexions are diamagnetic?

(i) \left [ Co(NH_{3})_{6} \right ]^{3+}

(ii) \left [ Mn(CN)_{6} \right ]^{3-}

(iii) \left [ Fe(CN)_{6} \right ]^{4-}

(iv) \left [ Fe(CN)_{6} \right ]^{3-}

 

Answers (1)

Option (i) and (iii) are the correct answers.

Explanation :

(a,c)

(a) Molecular orbital electronic configuration of Co^{3+} in \left [ Co(NH_{3})_{6} \right ]^{3+}is

Number of unpaired electron = 0

Magnetic property = Diamagnetic

(b) Molecular orbital electronic configuration of Mn^{3+} in \left [ Mn(CN)_{6} \right ]^{3-}

Number of unpaired electron = 2

Magnetic property = Paramagnetic

(c) Molecular orbital electronic configuration of Fe^{2+} in \left [ Fe(CN)_{6} \right ]^{4-}

Number of unpaired electron = 0

Magnetic property = Diamagnetic

(d) Molecular orbital electronic configuration of Fe^{3+} in \left [ Fe(CN)_{6} \right ]^{3-}

Number of unpaired electron = 1

Magnetic property = Paramagnetic

 

 

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