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  • The base of an equilateral triangle with side 2a lies along the y-axis such that the mid-point of the base is at the origin. Find vertices of the triangle.

Q : 2 The base of an equilateral triangle with side 2a  lies along the y-axis such that the mid-point of the base is at the origin.  Find vertices of the triangle. 

Answers (1)

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It is given that it is an equilateral triangle and the length of all sides is 2a
The base of the triangle lies on the y-axis such origin is the midpoint
Therefore,
Coordinates of points A and B are (0,a) \ \ and \ \ (0,-a)  respectively
Now,
Apply Pythagoras' theorem in triangle AOC
AC^2=OA^2+OC^2
(2a)^2=a^2+OC^2
OC^2= 4a^2-a^2=3a^2
OC=\pm \sqrt3 a
Therefore, the coordinates of the vertices of the triangle are

(0, a),(0,-a) $ and $(\sqrt{3} a, 0)$ or $(0, a),(0,-a) $ and $(-\sqrt{3} a, 0)

Posted by

Gautam harsolia

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