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  • The blades of a windmill sweep out a circle of area A.

Q21 (c)  The blades of a windmill sweep out a circle of area A. Assume that the windmill converts 25% of the wind’s energy into electrical energy, and thatA = 30 m ^2 , v = 36 Km /h and the density of air is 1.2 Kg m^{-3} What is the electrical power produced?

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It is given that 25 per cent of wind energy is converted into electrical energy.

Thus electric energy produced is :

                                                            =\ \frac{25}{100} \times \frac{1}{2}\ \rho At v^3 

or                                                =\ \frac{1}{8}\ \rho At v^3

Now the electric power is given by  :

                                                 Power\ =\ \frac{Energy}{Time}

or                                                                =\ \frac{\frac{1}{8}\ \rho At v^3}{t}\ =\ {\frac{1}{8}\ \rho A v^3}

or                                                                 =\ {\frac{1}{8}\ \times 1.2\times 30 \times (10)^3}

or                                                                 =\ 4.5\ KW

Posted by

Devendra Khairwa

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