The coefficients of xn in the expansion of (1 + x)2n and (1 + x)2n ~1 are in the ratio
(a) 1 : 2
(b) 1 : 3
(c) 3 : 1
(d) 2:1
The answer is the option (d) 2:1
2nCn is the coefficient of xn in the expansion of (1+x)2n
&2n-1Cn is the coefficient of xn in the expansion of (1+x)2n-1
= (2n)!n!(n-1)!/(2n-1)!n!n!
= 2n(2n-1)!n!(n-1)!/n!n(n-1)!(2n-1)!
= 2/1
= 2:1