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4.4 The decomposition of dimethyl ether leads to the formation of $CH_{4}$ , $H_{2}$ and $CO$ and the reaction rate is given by $Rate=k\left [ CH_{3}OCH_{3} \right ]^{3/2}$
The rate of reaction is followed by increase in pressure in a closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,
$Rate=k\left [ P_{CH_{3}OCH_{3} \right ]^{3/2}$
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants?

Answers (1)

best_answer

Given that

$rate = k(P_{CH_{3}OCH_{3}})^{3/2}$

So, the unit of rate is bar/min.( $bar\ min^{-1}$ )

And thus the unit of k = unit of rate $/(bar)^{3/2}$

$\\=bar\ min^{-1}/(bar)^{3/2}\\ =bar^{-1/2}min^{-1}$

Posted by

manish

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