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4 The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

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The diagonal of a quadrilateral shaped field is 24 m

the perpendiculars are 8 m and 13 m.

the area of the field =

$\frac{1}{2}\times d\times (h1+h2)$

$=\frac{1}{2}\times 24\times (13+8)$

$=12\times 21$

$=252 m^{2}$

Posted by

seema garhwal

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