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  • The diameter of zinc atom is 2.6 Angstrom. Calculate (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

2.37    The diameter of zinc atom is 2.6 Å. Calculate (b) number of atoms present in a length of 1.6 cm if the zinc atoms are arranged side by side lengthwise.

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The number of atoms present in a length of 1.6\ cm will be:

= \frac{1.6\times10^{-2}m}{2.6\times10^{-10}m} = 0.6153\times10^8m

= 6.153\times10^7

Posted by

Divya Prakash Singh

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