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2.53    The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35 V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

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Given work function of the metal, W and the Wavelength, \lambda = 256.7\ nm

From the Law of conservation of energy, the energy of an incident photon E is equal to the sum of the work function W of radiation and its kinetic energy K.E i.e.,

The energy of incident radiation

E = \frac{hc}{\lambda} = \frac{(6.626\times10^{-34}Js)(3.0\times10^8)m/s}{256.7\times10^{-9}m}

     = 7.74\times10^{-19} J  Or 

     = \frac{7.74\times10^{-19}J}{1.602\times10^{-19}}eV = 4.83\ eV  

Since the potential applied gives the kinetic energy to the radiation, therefore K.E of the electron = 0.35\ eV

Therefore, Work Function W = 4.83 - 0.35 = 4.48\ eV

Posted by

Divya Prakash Singh

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