Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The equilibrium constant for a reaction is 10. What will be the value of delta G ? R = 8.314 JK–1 mol–1, T = 300 K.

6.20  The equilibrium constant for a reaction is 10. What will be the value of   

             \Delta G ^ \ominus ? R = 8.314 JK ^{-1} mol ^{-1} , T = 300 K  

Answers (1)

best_answer

Given values are,
R = 8.314 JK ^{-1} mol ^{-1} , T = 300 K
and equilibrium constant  = 10

It is known that,
\Delta G^o = -2.303\ RT \log K_{eq}
           \\=-2.303(8.314)(300)\log 10\\ =-5744.14 Jmol^{-1}\\ =-5.744 kJmol^{-1}

Hence the value of \Delta G^o is -5.744 kJ/mol

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 history paper 2025 moderately difficult, tested students’ understanding
anam-khan

CBSE Class 12 Computer Science Exam Analysis 2025: Paper 'moderate', but 'tougher' than last three years
anam-khan

CBSE Class 12 Accountancy Exam Analysis 2025: Paper ‘moderate', includes application-based questions

Latest Question