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  • The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively (A) 4 and 24 (B) 5 and 30 (C) 6 and 36 (D) 3 and 24

The father’s age is six times his son’s age. Four years hence, the age of the father will be four times his son’s age. The present ages, in years, of the son and the father are, respectively
(A) 4 and 24
(B) 5 and 30
(C) 6 and 36
(D) 3 and 24

Answers (1)

Answer:(C) 6 and 36
Solution:
According to questions at present father’s age is six times than son’s age.
Let son age = x
Father age = y
y = 6x … (1)
After 4 years Father’s age will be four times than son’s age. That is
y + 4 = 4 (x + 4)
y + 4 = 4x + 16
4x – y + 12 = 0 …(2)
Put y = 6x in equation (2)
4x – 6x + 12 = 0
+ 2x = + 12
x = \frac{12}{2} = 6
Put x = 6 in equation (1)
y = 6 (6) = 36
y = 36
Hence present age of father is 36 and son is 6.

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