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  • The following results have been obtained during the kinetic studies of the reaction: 2A + B gives C + D

The following results have been obtained during the kinetic studies of the reaction:
             2A + B \rightarrow C + D

          

           Determine the rate law and the rate constant for the reaction.

Answers (1)

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Let's assume the rate of reaction wrt A is x and wrt B is y . So, the rate of reaction is expressed as the rate =k[A]^x[B]^y

According to the given data,
\begin{aligned} & 6 \times 10^{-3}=k[0.1]^x[0.1]^y \\ & 7.2 \times 10^{-2}=k[0.3]^x[0.2]^y \\ & 2.88 \times 10^{-2}=k[0.3]^x[0.4]^y \\ & 2.4 \times 10^{-2}=k[0.4]^x[0.1]^y\end{aligned}

These are the equation 1, 2, 3, and 4 respectively

Now,  divide the equation(iv) by (i) we get,
4=(0.4 / 0.1)^x
from here we calculate that x=1

Again, divide equation (iii) by (ii)
4=(0.4 / 0.2)^y
from here we can calculate the value of y as 2

Thus, the rate law is now, the Rate =k[A][B]^2
So, \begin{aligned} k & =\text { rate } /[A][B]^2 \\ & =6 \times 10^{-3} /(0.1) \times(0.1)^2 \\ & =6 \mathrm{~L}^2 \mathrm{~mol}^{-2} \mathrm{~min}^{-1}\end{aligned}

Hence the rate constant of the reaction is =6 \mathrm{~L}^2 \mathrm{~mol}^{-2} \mathrm{~min}^{-1}

Posted by

manish

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