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The last two digits of the numbers 3400 are 01.
Answers (1)
The given statement is true.
Given: 3400 = (9)200
= (10 – 1)200
Thus, (10 – 1)200 = 200C0(10)200 – 200C1(10)199 + ….. – 200C199(10)1 + 200C200(1)200
= 10200 – 200 x 10199 + …. – 10 x 200 + 1
Therefore, the last two digits will be 01.
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