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Q25.    The longest side of a triangle is 3 times the shortest side and the third side is 2 cm shorter than the longest side. If the perimeter of the triangle is at least 61 cm, find the minimum length of the shortest side.

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Let the length of the smallest side be x cm.

 Then largest side = 3x cm.

Third side = 3x-2  cm.

Given: The perimeter of the triangle is at least 61 cm.

\therefore\, \, \, x+3x+(3x-2)\geq 61

     \Rightarrow \, \, \, 7x-2\geq 61

   \Rightarrow \, \, \, 7x\geq 61+2

  \Rightarrow \, \, \, 7x\geq 63

 \Rightarrow \, \, \, x\geq \frac{63}{7}

\Rightarrow \, \, \, x\geq 9

 Minimum length of the shortest side is 9 cm.

 

 

 

 

Posted by

seema garhwal

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