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7.56     The pH of milk, black coffee, tomato juice, lemon juice and egg white are 6.8, 5.0, 4.2, 2.2 and 7.8 respectively. Calculate corresponding hydrogen ion concentration in each

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We already know that p^H can be calculated as- -\log[H^+] 
to calculate the concentration of [H^+] = antilog (-p^H)

Thus, the hydrogen ion concentration of followings p^H values are-

(i)  p^Hof milk = 6.8
Since, p^H=-\log[H^+]
6.8 = -\log[H^+]
\log[H^+] = -6.8

[H^+] = anitlog(-6.8)

        = 1.5\times10^{-7}M

 

(ii) p^Hof black coffee = 5.0

Since, p^H=-\log[H^+]

5.0 =-\log[H^+]

\log[H^+]= -5.0

[H^+]= anitlog(-5.0)

= 10^{-5}M

 

(iii) p^H of tomato juice = 4.2

Since, p^H=-\log[H^+]

4.2 =-\log[H^+]

\log[H^+]= -4.2

[H^+]= anitlog(-4.2)

= 6.31\times10^{-5}M

 

(iv) p^H of lemon juice = 2.2

Since, p^H=-\log[H^+]

2.2 = -\log[H^+]

\log[H^+]= -2.2

[H^+]= anitlog(-2.2)

=6.31\times10^{-3}M

(v) p^H of egg white = 7.8

Since, p^H=-\log[H^+]

7.8 = -\log[H^+]

\log[H^+] = -7.8

[H^+]= anitlog(-7.8)

= 1.58\times10^{-8}M

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manish

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