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  • The point P (–2, 4) lies on a circle of radius 6 and centre C (3, 5).

The point P (–2, 4) lies on a circle of radius 6 and centre C (3, 5).

Answers (1)

Answer.     [False]
Solution.        
The radius of the circle is 6 and centre C(3, 5)
If point P(–2, 4) lies on the circle then the distance between the centre and point P is equal to the radius of the circle.
Distance\, between\, PC = \sqrt{\left ( x_{2}-x_{1} \right )^{2}+\left ( y_{2} -y_{1}\right )^{2}}
(x1, y1) = (-2, 4)             (x2, y2) = (3, 5)
PC= \sqrt{\left ( 3+2 \right )^{2}+\left ( 5-4 \right )^{2}}
PC=\sqrt{25+1}= \sqrt{26}
PC\neq radius\left ( 6 \right )
Hence, point P(–2, 4) not lies on the circle with centre C(3, 5).

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