Get Answers to all your Questions

header-bg qa

Q 12.8  The radius of the innermost electron orbit of a hydrogen atom is 5.3 \times 10 ^{-11}m. What are the radii of the n = 2 and n =3 orbits?

Answers (1)

best_answer

The radius of the orbit is proportional to the square of n.

For n=2 the radius of the orbit is

\\r_{2}=r_{1}\times 2^{2}\\ =5.3\times 10^{-11}\times 4\\ =2.12\times 10^{-10}\ m

For n=3 the radius of the orbit is

\\r_{3}=r_{1}\times 3^{2}\\ =5.3\times 10^{-11}\times 9\\ =4.77\times 10^{-10}\ m

Posted by

Sayak

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads