Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • The reaction, CO(g) + 3H_2(g) CH_4(g) + H_2O(g) is at equilibrium at 1300 K in a 1L flask. It also contain 0.30 mol of CO, 0.10 mol of H_2 and 0.02 mol of H_2O and an unknown amount of CH_4 in the flask.

7.34     The reaction,

                  CO(g)+3H_{2}(g)\rightleftharpoons CH_{4}(g)+H_{2}O(g)

              is at equilibrium at 1300 K in a 1L flask. It also contain 0.30 mol of CO, 0.10 mol of H_2 and 0.02 mol of H_2O and an unknown amount of CH4 in the flask. Determine the concentration of CH4 in the mixture. The equilibrium constant, Kc for the reaction at the given temperature is 3.90.

Answers (1)

best_answer

Given that,
Total volume = 1L
0.3 mol of CO, 0.10 mol of dihydrogen(H_2)and the 0.02 mol of water(H_2O)
the equilibrium constant = 3.90

Let x be the concentration of methane at equilibrium. The given reaction is-

                                        CO(g)+3H_{2}(g)\rightleftharpoons CH_{4}(g)+H_{2}O(g)
At equilibrium,                    0.3 mol/L         0.1 mol/L        x           0.02 mol/L

Therefore,

K_c = \frac{0.02\times x}{(0.3)(0.1)}=3.90
        \Rightarrow x = \frac{(3.9)(0.3)(0.1)^3}{(0.02)}
                   =5.85\times 10^{-2}

Thus the concentration of methane at equilibrium is =5.85\times 10^{-2}

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE wants international boards reined in; letter to education ministry seeks directions for AIU
anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens

Latest Question