The solubility product of is . Calculate its solubility in gL-1 and also find out the pH of this solution. (Atomic mass of ).
As per the information given in the question,
Hence, we can write the equation of disassociation of as -
At t=0 | 1 | 0 | 0 |
At,t=t | 1-s | s | 3s |
It is known to us that,
Now, molar mass of
Therefore, solubility = molar mass x s
Now, it is known to us that,
pH = 14 - pOH
[OH]= 3s = 3 × 10-3
pOH= 3-log3
pH = 14 – 3 + log3
= 11.4771
Therefore, we can conclude that the solubility in g/L will be 7.8×10-2 g/L amd the pH of the solution will be 11.47.