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Q3 (a) The stress-strain graphs for materials A and B are shown in Fig. 9.12. The graphs are drawn to the same scale. Which of the materials has the greater Young’s modulus?
Answers (1)
Answer: (a) A (b) A
(a) For a given strain, the stress for material A is more than it is for material B, as shown in the two graphs.
$$
\text { Young's modulus }=\frac{\text { Stress }}{\text { Strain }}
$$
For a given strain, if the stress for a material is more, then Young’s modulus is also greater for that material. Therefore, Young’s modulus for material A is greater than it is for material B.
(b) The amount of stress required for fracturing a material, corresponding to its fracture point, gives the strength of that material. The fracture point is the extreme point in a stress-strain curve. It can be observed that material A can withstand more strain than material B. Hence, material A is stronger than material B.
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