Q.7 The sum of three consecutive multiples of 8 is 888. Find the multiples.
Let x be the multiple of 8.
Then the three consecutive integers (multiple of 8) are x, x+8, x+16.
Given their sum is 888,
thus the equation becomes: x + x + 8 + x + 16 = 888
or 3x + 24 = 888
Transposing 24 to the RHS
3x = 888 - 24 = 864
Now dividing both sides by 3, we get
Thus the required consecutive integers are 288, 296, 304.