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Q 12.15 (b) The total energy of an electron in the first excited state of the hydrogen atom is about –3.4 eV.
What is the potential energy of the electron in this state?
Answers (1)
Total Energy= Potential energy + Kinetic Energy
E=U+K
U=E-K
U=-3.4-3.4
U=-6.8 eV
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