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The total number of 9-digit numbers which have all different digits is
A. 10!
B. 9!
C. 9 × 9!
D. 10×10!
Answers (1)
The answer is the option (c).
We have to form 9-digit number, which has all different digits.
First digit from the left can be filled in 9 ways excluding 0. After this, nine digits are left including ‘0’. Remaining 8 places can be filled with these nine digits in ways. So, total numbers=
View full answer
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