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  • The value of K_c for the reaction 3O_2 (g) 2O_3 (g) is 2.0 ×10^–50 at 25°C. If the equilibrium concentration of O_2 in air

7.33     The value of Kc for the reaction 3O_{2}(g)\rightleftharpoons 2O_{3}(g) is 2.0 ×10-50 at 25°C. If the equilibrium concentration of O2 in air at 25°C is 1.6 ×10-2, what is the concentration of O3?

Answers (1)

best_answer

We have,

equilibrium constant of the reaction = 2\times 10^{-50}
the concentration of dioxygen [O_2] = 1.6 \times 10^{-2}

the given reaction is-

3O_{2}(g)\rightleftharpoons 2O_{3}(g)
Then we have,
(equilibrium constant)
K_c = [O_3 (g)]^2 / [O_2 (g)]^3

\\2\times 10^{-50} = [O_3]^2/(1.6\times 10^{-2})^3\\ {[O_3]^2} = 2\times 10^{-50}\times(1.6\times 10^{-2})^3

             =8.192\times 10^{-56}

              {[O_3]}=\sqrt{8.192\times 10^{-56}} = 2.86 \times 10^{-28}

Thus the concentration of dioxygen is 2.86 \times 10^{-28}

Posted by

manish

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