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The value of the expression (cos2 23° – sin2 67°) is positive.

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Answer.      [False]            
Solution.   (cos2 23° – sin2 67°)

\left ( \cos ^{2}\left ( 90^{\circ}-67^{\circ} \right )-\sin ^{2}67^{\circ} \right )  \left ( \because 23^{\circ}= 90^{\circ}-67^{\circ} \right )
= Sin267° - sin267°   (cos(90-θ) = sin θ)
= 0
Hence the value of the expression is neutral
So, the given statement is false.

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