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Q : 6    The volume of a right circular cone is \small 9856\hspace{1mm}cm^3. If the diameter of the base is 28 cm, find

            (ii) slant height of the cone 
 

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Given, a right circular cone.

The volume of the cone = \small 9856\hspace{1mm}cm^3

The radius of the base of the cone = r = \frac{28}{2} = 14\ cm

And the height of the cone =  h = 48\ cm

(ii) We know, Slant height, l = \sqrt{r^2+h^2}

\\ \Rightarrow l = \sqrt{14^2+48^2} \\ \Rightarrow l = \sqrt{196+2304} = \sqrt{2500} \\ \Rightarrow l = 50\ cm

Therefore, the slant height of the cone is 50\ cm

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HARSH KANKARIA

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