There are 10 persons named P1,P2,P3, ... P10. Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements.

Name: There are 10 persons named P1,P2,P3, ... P10. Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements.
Uploaded: Sat, 2020-09-12 23:48
Description: There are 10 persons named P1,P2,P3, ... P10. Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements.

#Permutations and Combinations
#Exemplar Maths for Class 11
#Maths
#NCERT

#1.3
#8.5
#Fill in the blanks
#Match the column
#Short Answer type
#Long answer type
#True-false based type
#Multiple Choice Questions (MCQs)

1.0
2.0
3.0
4.0
5.0
6.0
7.0
8.0
9.0
10.0
11.0
12.0
13.0
14.0
15.0
16.0
17.0
18.0
19.0
20.0
21.0
22.0
23.0
24.0
25.0
26.0
27.0
28.0
29.0
30.0
31.0
32.0
33.0
34.0
35.0
36.0
37.0
38.0
39.0
40.0
41.0
42.0
43.0
44.0
45.0
46.0
47.0
48.0
49.0
50.0
51.0
52.0
53.0
54.0
55.0
56.0
57.0
58.0
59.0
60.0
61.0
62.0
63.0
64.0

There are 10 persons named $P_1,P_2,P_3, ... P_{10}$ . Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P₁ must occur whereas P₄ and P₅ do not occur. Find the number of such possible arrangements. [Hint: Required number of arrangement $=7C_4\times 5!$ ]

Answers (1)

Given that $P_1,P_2,P_3, ... P_{10}$

persons out of which 5 are to be arranged but $P_1$ must occur

whereas P₄and P₅ never occur. So, now we only have to select 4 out of 7 persons

Number of selections= $^7C_4=35$

Number of the arrangement of 5 persons= $35*5!=35*120=4200$

Posted by

infoexpert21

View full answer

Exams

Colleges

Predictors

Resources

Quick links

Quick Links

Exams

Colleges

Resources

Colleges

Resources

Exams

Exams

Colleges

Resources

Diploma Colleges

Other Exams

Exams

Resources

Upcoming Events

Exams

Top Schools

Products & Resources

NCERT Study Material

Top Countries

Student Visas

Exams

Colleges

Exams

Colleges

Upcoming Events

Resources

Exams

Colleges & Courses

Predictors

Resources

Online Courses

Products

Engineering Preparation

Medical Preparation

Top Streams

Specializations

Resources

Top Providers

Exams

Colleges

Predictors

Resources

Resources

Exams

Colleges

Predictors & E-Books

Exams

Predictors & Articles

Colleges

Resources

Exams

Colleges

Resources

Top Courses & Careers

Colleges

Exams

Resources

Get Answers to all your Questions

There are 10 persons named . Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P1 must occur whereas P4 and P5 do not occur. Find the number of such possible arrangements. [Hint: Required number of arrangement ]

Answers (1)

Posted by

infoexpert21

Similar Questions

Latest Question

Ask your Query

Welcome Back :)

Register to post Answer

Welcome Back :)

There are 10 persons named $P_1,P_2,P_3, ... P_{10}$ . Out of 10 persons, 5 persons are to be arranged in a line such that in each arrangement P₁ must occur whereas P₄ and P₅ do not occur. Find the number of such possible arrangements. [Hint: Required number of arrangement $=7C_4\times 5!$ ]