Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Twenty seven solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area S′. Find the (i) radius r′ of the new sphere.

Q : 9    Twenty seven solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area \small S'. Find the

            (i) radius \small r' of the new sphere

Answers (1)

best_answer

Given,

The radius of a small sphere = r

The radius of the bigger sphere = r'

\thereforeThe volume of each small sphere= \frac{4}{3}\pi r^3

And, Volume of the big sphere of radius r'= \frac{4}{3}\pi r'^3

According to question,

27\times\frac{4}{3}\pi r^3=\frac{4}{3}\pi r'^3

\\ \Rightarrow r'^3 = 27\times r^3 \\ \Rightarrow r' = 3\times r

\therefore r' = 3r

Posted by

HARSH KANKARIA

View full answer

Similar Questions

Trending Articles/News

anam-khan

Board Exam Date 2025 Live: Bihar Class 10, 12 model papers out, time table soon; updates on CBSE, UP

Latest Question