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  • Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz.

Q.15.18 Two sitar strings A and B playing the note ‘Ga’ are slightly out of tune and produce beats of frequency 6\: Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3\: Hz.  If the original frequency of A is 324\: Hz, what is the frequency of B?

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\\\nu _{A}=324Hz\\ Beat\ frequency(b)=6Hz\\ \nu _{B}=\nu _{A}\pm b\\ \nu _{B}=318Hz \\or \\\nu _{B}=330Hz

Since frequency increases with an increase in Tension, the frequency of string A must have decreased. Therefore \nu _{B}=318Hz.(If it were 330 Hz the beat frequency would have increased with decrease in Tension in string A)

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