Use the following data to calculate for NaBr.
for sodium metal = 108.4 kJ mol–1
Ionization enthalpy of sodium = 496 kJ mol-1
Electron gain enthalpy of bromine = – 325 kJ mol-1
Bond dissociation enthalpy of bromine = 192 kJ mol-1
for NaBr (s) = – 360.1 kJ mol-1
In order to calculate the lattice enthalpy of NaBr,
(i)
(ii)
(iii)
(iv)