Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Using the given pattern, find the missing numbers. 1^2 + 2^2 + 2^2 = 3^2 ; 2^2 + 3^2 + 6^2 = 7^2

Q.6 Using the given pattern, find the missing numbers.

1^{2}+2^{2}+2^{2}=3^{2} 

2^{2}+3^{2}+6^{2}=7^{2}

3^{2}+4^{2}+12^{2}=13^{2} 

4^{2}+5^{2}+\;-\; ^{2} = 21^{2}

5^{2}+-^{2}+30^{2}= 31^{2}

6^{2}+7^{2}+-^{2}= -^{2} 

Answers (1)

best_answer

Patter is clearly visible.

First two numbers and the last two numbers are the consecutive numbers.

Moreover, the third number is obtained when the first is multiplied with the second number.

So required numbers can be found. 

i.e., 4 \times 5 = 20                and           6 \times 7 = 42

hence         4^{2} + 5^{2} + 20^{2} = 21^{2}

and             5^{2} + 6^{2} + 30^{2} = 31^{2}

and              6^{2} + 7^{2} + 42^{2} = 43^{2}   

Posted by

Devendra Khairwa

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST 2025 Class 6 registration ends today; apply at navodaya.gov.in

Latest Question