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  • Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:y = x^2 + 2x + C : y' - 2x - 2 = 0

2. Verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation:

       y = x^2 + 2x + C\qquad:\ y' -2x - 2 =0

Answers (1)

best_answer

Given,

y = x^2 + 2x + C

Now, differentiating both sides w.r.t. x,

\frac{\mathrm{d}y }{\mathrm{d} x} = \frac{\mathrm{d} }{\mathrm{d} x}(x^2 + 2x + C) = 2x + 2

Substituting the values of y’ in the given differential equations,

y' -2x - 2 =2x + 2 - 2x - 2 = 0= RHS.

Therefore, the given function is the solution of the corresponding differential equation.

Posted by

HARSH KANKARIA

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