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  • What is K_c for the following equilibrium when the equilibrium concentration of each substance is: [SO_2]= 0.60M, [O_2] = 0.82M and [SO_3] = 1.90M ?

7.2     What is Kc for the following equilibrium when the equilibrium concentration of each substance is: [SO2]= 0.60M, [O2] = 0.82M and [SO3] = 1.90M ? 

               2SO_{2}_{(g)}+O_{2}_{(g)}\rightleftharpoons 2SO_{3}_{(g)}

Answers (1)

best_answer

Followings are the given information values to solve the above problems-
\\{[SO_{2}]}= 0.60 M\\ {[O_{2}]}=0.82M\\ {[SO_{3}]}=1.90M
The given chemical equation is -

2SO_{2}_{(g)}+O_{2}_{(g)}\rightleftharpoons 2SO_{3}_{(g)}

The equilibrium constant for this reaction is expressed as;
K_c=\frac{[SO_{3}]^2}{[SO_{2}]^2[O_{2}]}
        
       \\=\frac{[1.90]^2}{[0.60]^2[0.82]}\\ =12.22 M^{-1}(approx)

Posted by

manish

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