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  • What is the lowest total resistance that can be secured by combinations of four coils of resistance 4 Omega, 8 Omega, 12 Omega, 24 Omega ?

    What is (b) the lowest total resistance that can be secured by combinations of four coils of resistance                       4\; \Omega , 8\; \Omega ,12\; \Omega ,24\; \Omega ?

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(b) the lowest total resistance is R is obtained when all the resistors are connected in parallel.

\frac{1}{R}=\frac{1}{4}+\frac{1}{8}+\frac{1}{12}+\frac{1}{24}

\frac{1}{R}=\frac{6+3+2+1}{24}=\frac{12}{24}

R=\frac{24}{12}=2

Posted by

seema garhwal

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