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2.15 What is the maximum number of emission lines when the excited electron of a H atom in n = 6 drops to the ground state?

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The number of lines produced when an electron from $n^{th}$ shell drops to the ground state:

$= \frac{n(n-1)}{2}$ .

According to the question, the maximum number of emission lines when the excited electron of an H atom in $n=6$ drops to the ground state will be:

$\frac{6(6-1)}{2} = 15$

These are produced because of the following transitions:

$6\rightarrow5$ $6\rightarrow4$ $6\rightarrow3$ $6\rightarrow2$ $6\rightarrow1$

$5\rightarrow4$ $5\rightarrow3$ $5\rightarrow2$ $5\rightarrow1$

$4\rightarrow3$ $4\rightarrow2$ $4\rightarrow1$

$3\rightarrow2$ $3\rightarrow1$

$2\rightarrow1$

Posted by

Divya Prakash Singh

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