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  • What is the number of photons of light with a wavelength of 4000 pm that provide 1J of energy?

2.8    What is the number of photons of light with a wavelength of 4000 pm that provide 1J of energy?

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Given the wavelength of light \lambda = 4000\ pm = 4000\times10^{-12}m = 4\times10^{-9} m.

and Energy is 1J of energy:

E = Nh\nu = Nh\frac{c}{\lambda}

Therefore, the number of photons of light with a wavelength of 4000 pm that provides 1J of energy is:

N = E\times\frac{\lambda}{hc} = (1J)\times\left ( \frac{4\times10^{-9}m}{(6.626\times10^{-34}J.s)\times(3.0\times10^8 ms^{-1})} \right )

= 2.012\times10^{16}\ photons.

 

Posted by

Divya Prakash Singh

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