When 0.1 mol is treated with an excess of
, 0.2 mol of
are obtained. The conductivity of the solution will correspond to
(i) 1:3 electrolyte
(ii) 1:2 electrolyte
(iii) 1:1 electrolyte
(iv) 3:1 electrolyte
Option (ii) is the correct answer.
Explanation:
One mole of chloride ion gets precipitated by one mole of .
, is obtained when 0.1 mole of
is treated with
in excess. So this leaves two free chloride ions in the solution of electrolyte for every 1 mole reaction.
Hence the molecular formula should be and the solution of electrolyte should contain
and two Cl as their constituent ions. Therefore, it is an 1:2 electrolyte.