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When a metal of group 1 was dissolved in liquid ammonia, the following observations were obtained:
(i) Blue solution was obtained initially.
(ii) On concentrating the solution, blue colour changed to bronze colour.

How do you account for the blue colour of the solution? Give the name of the product formed on keeping the solution for some time.

Answers (1)

(i) Alkali metals dissolve in liquid ammonia, and ammoniated electrons get excited to a higher level which imparts a blue colour to the solution.

M+(x+y)NH_{3}\rightarrow \left [\left (M(NH_{3})_{x} \right ) \right ]^{+} e (NH_{3})_{y}^{-}

(ii) In a concentrated solution, blue colour changes to bronze due to the formation of clusters of the metal ion. On keeping the solution for some time, blue solution liberates H2 gas with the formation of amide.

M^{+}(aq)+e^{-}+NH_{3}(l)\rightarrow MNH_{2}(aq)+12H_{2}(g)

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