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When an oxide of manganese (A) is fused with KOH in the presence of an oxidizing agent and dissolved in water, it gives a dark green solution of compound (B). Compound (B) disproportionates in neutral or acidic solution to give purple compound (C). An alkaline solution of compound (C) oxidises potassium iodide solution to a compound (D) and compound (A) is also formed. Identify compounds A to D and also explain the reactions involved.

Answers (1)

The compounds (i), (ii), (iii) and (iv) are given as under:

A=MnO_{2}\; \; \; \; \; \; B=K_{2}MnO_{4}\; \; \; \; \; \; C=KMnO_{4}\; \; \; \; \; \; \; \; D=KIO_{3}

                                2MnO_{2}\; (A)+4KOH+O_{2}\rightarrow 2K_{2} MnO_{4} (B)+2H_{2} O

                                      3MnO_{4}^{2-}+4H^{+}\rightarrow 2MnO _{4}^{-}+MnO_{2}+2H_{2} O

                               2MnO_{4}^{-}+H_{2} O+KI\rightarrow 2MnO_{2} (i)+2OH^{-}+KIO_{3} (iv).

 

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