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  • When water is added to compound (A) of calcium, solution of compound (B) is formed. When carbon dioxide is passed into the solution, it turns milky due to the formation of compound (C).

When water is added to compound (A) of calcium, solution of compound (B) is formed. When carbon dioxide is passed into the solution, it turns milky due to the formation of compound (C). If excess of carbon dioxide is passed into the solution milkiness disappears due to the formation of compound (D). Identify the compounds A, B, C and D. Explain why the milkiness disappears in the last step.

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Solution B which turns milky on passing CO_2 is lime water Ca(OH)_{2} (Calcium hydroxide)and Compound C which gives milky appearance is CaCO_{3} (Calcium carbonate). On passing excess of CO_2  milkiness disappears due to the formation of Ca(HCO_{3})_{2}(Calcium bicarbonate). Compound A reacts with water to give B. A is CaO.

CaO A+H_{2}O\rightarrow Ca(OH)_{2} (B)

Ca(OH)_{2}(B)+CO_{2} \rightarrow CaCO_{3} (C)+H_{2}O

Ca(OH)_{2}(B)+CO_{2}+H_{2}O\rightarrow Ca(HCO_{3})_{2} (D)

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