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Q : 4      Which of the following are APs ? If they form an AP, find the common difference d and write three more terms.

              (iii)  \small -1.2,-3.2,-5.2,-7.2,...

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Given series is
\small -1.2,-3.2,-5.2,-7.2,...
Now,
first term to this series is = -1.2
Now,
a_1 = -1.2 \ \ and \ \ a_2 = -3.2 \ \ and \ \ a_3 = -5.2 \ \ and \ \ a_4 = -7.2
a_2-a_1 = -3.2-(-1.2) =-3.2+1.2=-2
a_3-a_2 = -5.2-(-3.2) =-5.2+3.2 = -2
a_4-a_3=-7.2-(-5.2)=-7.2+5.2=-2
We can clearly see that difference between terms are equal  and equal to -2
Hence, given series is in AP
Now, next three terms are
a_5=a_4+d = -7.2-2 =-9.2
a_6=a_5+d = -9.2-2 =-11.2
a_7=a_6+d = -11.2-2 =-13.2
Therefore, next three terms of given series are  -9.2,-11.2,-13.2

Posted by

Gautam harsolia

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