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  • White phosphorus reacts with chlorine and the product hydrolyses in the presence of water Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water

White phosphorus reacts with chlorine and the product hydrolyses in the presence of water. Calculate the mass of HCl obtained by the hydrolysis of the product formed by the reaction of 62 g of white phosphorus with chlorine in the presence of water.

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Phosphorus reacts with Cl_{2} as : P_{4}+6Cl_{2}\rightarrow 4PCl_{3};

PCl_{3}+3H_{2}O\rightarrow H_{3}PO_{3}+3HCl] \times 4 \left ( PCl_{3}\; is \; hydrolysed \right )

P_{4}+6Cl_{2}+12H_{2}O\rightarrow 4H_{3}PO_{3}+12HCl

Moles of white P=\frac{62}{124}=0.5\; mol

1 mol of white P_{4} produce HCl=12\; mol

0.5 mol of white P_{4} will produce HCl=12\; \times 0.5=6\; mol

Mass of HCl=6\times 36.5=219.0\; g

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