Without repetition of the numbers, four digit numbers are formed with the numbers 0, 2, 3, 5. The probability of such a number divisible by 5 is
A. 1/5
B. 4/5
C. 1/30
D. 5/9
Given digits: 0, 2, 3, 5
Now, we now that if a no. is divisible by 5, then the digit in the units place should be either 0 or 5
Now, if units place is 0, then
3 |
2 |
1 |
1 |
Now, the first three places can be filled in 3! Ways
= 3 x 2 x 1 x 1
= 6
Now, if units place is 5, then,
2 |
1 |
1 |
1 |
Here, we can fill the first two places in 2 ways & the 2nd and 3rd place in 2! Ways
= 2 x 2 x 1 x 1
= 4
Thus, the total no. of ways = 6 + 4
= 10
= n (E)
Now, total no. of ways to arrange the given digits to form 4 – digits without repetition is 3 x 3 x 2 x 1
= 18
Probability = no. of favorable outcomes/ total no. of outcomes
= 10 /18
= 5 /9
Thus, option D is the correct answer.