Q.2 Write a Pythagorean triplet whose one member is.
(iv) 18
For any natural number m > 1, 2m, and forms a Pythagorean triplet.
So if we take,
But the value of m will not be an integer.
Now we take,
but the value of m will not be an integer.
If we take 2m = 18
then m = 9
Then 81 - 1 = 80 and 81 + 1 = 82.
Therefore the required combination is 18, 80 and 82