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6.   Write the first five terms of each of the sequences in Exercises 1 to 6 whose nth terms are:

    a _n = n \frac{n^2 + 5}{4}

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Given : a _n = n \frac{n^2 + 5}{4}

a _1 = 1. \frac{1^2 + 5}{4}=\frac{6}{4}=\frac{3}{2}

a _2 = 2. \frac{2^2 + 5}{4}=\frac{18}{4}=\frac{9}{2}

a _3 = 3. \frac{3^2 + 5}{4}=\frac{42}{4}=\frac{21}{2}

a _4 = 4. \frac{4^2 + 5}{4}=\frac{84}{4}=21

a _5 = 5. \frac{5^2 + 5}{4}=\frac{150}{4}=\frac{75}{2}

Therefore, the required number of terms =\frac{3}{2},\frac{9}{2},\frac{21}{2},21,\frac{75}{2}

Posted by

seema garhwal

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