Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Write the Nernst equation and emf of the following cells:

3.5    Write the Nernst equation and emf of the following cells at 298 K:

           (ii) Fe(s)|Fe^{2+}(0.001M)||H^{+}(1M)|H_{2}(g)(1 bar)|Pt(s)

Answers (1)

best_answer

The nernst equation for this gives :

                                                E_{Cell} = E_{cell}^{\circ}\ - \frac{0.0591}{n}log \frac{[Fe^{+2}]}{\left [ H^+ \right ]^2}

This gives :                                        = 0 - (-0.44)- \frac{0.0591}{2}log \frac{0.001}{1^2}

or                                                      = 0.44 - 0.02955(-3) = 0.53\ V             

Thus the emf of the given galvanic cell is 0.53 V.

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 board exams 2025 to have 50% competency-based questions; no change in 10th
anam-khan

CBSE Class 12 board exams 2024 over; expected result date, trends of last 10 years
anam-khan

CBSE Class 12 accountancy board exam analysis 2024 out; paper rated easy, balanced

Latest Question