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2.5 Yellow light emitted from a sodium lamp has a wavelength (\lambda) of 580 nm. Calculate the frequency (ν) and wavenumber (\nu) of the yellow light.

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Given the wavelength of the yellow light emitted from a sodium, lamp is \lambda = 580nm = 580\times10^{-9}m.

And the frequency will be:

\nu =\frac{c}{\lambda} = \frac{3.0\times10^8m/s}{580\times10^{-9}m} = 5.17\times10^{14}s^{-1}

Therefore the wavenumber,

\vartheta =\frac{1}{\lambda} = \frac{1}{580\times10^{-9}m} = 1.72\times10^{6}m^{-1}

Posted by

Divya Prakash Singh

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