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Explain Solution for RD Sharma Maths Class 12 Chapter 17 Maxima and Minima Exercise Fill in the blanks Question 8 maths textbook solution

Answers (1)

Answer:

              \frac{1}{\sqrt{3}}

Hint:

For maxima or minima we must have {f}'\left ( x \right )=0

Solution:

Let the number bex , then the cube of the number is x^{3}

f\left ( x \right )=x-x^{3}

{f}'\left ( x \right )=1-3x^{2}

\begin{aligned} &\text { Put } f^{\prime}(x)=0 \\ &1-3 x^{2}=0 \\ &x=\pm \frac{1}{\sqrt{3}} \\ &f^{\prime \prime}(x)=-6 x[\text { Negative }] \\ &x=\frac{1}{\sqrt{3}} \end{aligned}

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